NEET 2027 POSSIBLE QUESTIONSPART 89 — ADVANCED PRACTICE SETEnglish–Urdu Version | انگلش اردو ورژنExam Target: NEET UG 2027Total Questions: 38Suggested Time: 45–50 minutesSubjects: Physics, Chemistry and BiologyTopics / Mauzuaat:Physics: Dual Nature of Matter and Radiation — Maddah aur Shuaon ki Dohrī FitratChemistry: Chemical Kinetics — Kimiyai Raftar-e-AmalBiology: Biodiversity and Conservation — Hayati Tanawwu aur TahaffuzDisclaimer: These questions are independently prepared for practice. They are not official NTA questions, and there is no guarantee that they will appear in NEET 2027.Aham Wazahat: Yeh sawalat NEET 2027 ki tayari ke liye mashqi sawalat hain. Yeh NTA ke rasmi sawalat nahin hain, aur in ke asal imtihan mein aane ki koi guarantee nahin hai.SECTION A: PHYSICS

NEET 2027 POSSIBLE QUESTIONS

PART 89 — ADVANCED PRACTICE SET

English–Urdu Version | انگلش اردو ورژن

Exam Target: NEET UG 2027

Total Questions: 38

Suggested Time: 45–50 minutes

Subjects: Physics, Chemistry and Biology

Topics / Mauzuaat:

Physics: Dual Nature of Matter and Radiation — Maddah aur Shuaon ki Dohrī Fitrat

Chemistry: Chemical Kinetics — Kimiyai Raftar-e-Amal

Biology: Biodiversity and Conservation — Hayati Tanawwu aur Tahaffuz

Disclaimer: These questions are independently prepared for practice. They are not official NTA questions, and there is no guarantee that they will appear in NEET 2027.

Aham Wazahat: Yeh sawalat NEET 2027 ki tayari ke liye mashqi sawalat hain. Yeh NTA ke rasmi sawalat nahin hain, aur in ke asal imtihan mein aane ki koi guarantee nahin hai.

SECTION A: PHYSICS

Chapter: Dual Nature of Matter and Radiation

Maddah aur Shuaon ki Dohrī Fitrat

Multiple-Choice Questions (MCQs)

Q1. The energy of a photon of frequency f is:

A. hf

B. h/f

C. f/h

D. hc/f

Urdu: Agar photon ki frequency f ho, to us ki energy kya hogi?

A. hf

B. h/f

C. f/h

D. hc/f

Q2. The work function of a metal is 2 eV. Find the approximate threshold frequency.

Given:

[ h=6.63\times10^{-34},\text{J s} ]

[ 1,\text{eV}=1.6\times10^{-19},\text{J} ]

A. 2.4\times10^{14},\text{Hz}

B. 4.8\times10^{14},\text{Hz}

C. 6.0\times10^{14},\text{Hz}

D. 8.0\times10^{14},\text{Hz}

Urdu: Ek ma'adin ka work function 2 eV hai. Photoelectric emission ke liye zaroori minimum frequency taqreeban kitni hogi?

Q3. In the photoelectric effect, the maximum kinetic energy of emitted electrons primarily depends on:

A. Intensity of incident light

B. Frequency of incident light

C. Surface area of the metal

D. Number of photons alone

Urdu: Photoelectric effect mein nikalne wale electrons ki maximum kinetic energy bunyadi taur par kis cheez par munhasir hoti hai?

A. Roshni ki shiddat

B. Roshni ki frequency

C. Ma'adin ki satah ka raqba

D. Sirf photons ki tadaad

Q4. If the incident frequency is below the threshold frequency, increasing intensity will:

A. Increase maximum kinetic energy

B. Increase stopping potential

C. Eventually cause emission

D. Not produce emission under the usual single-photon model

Urdu: Agar roshni ki frequency threshold frequency se kam ho, to intensity barhane se kya hoga?

A. Maximum kinetic energy barhegi.

B. Stopping potential barhega.

C. Kuch waqt baad electrons nikalne lagenge.

D. Aam single-photon model ke mutabiq electrons ka ikhraj nahin hoga.

Q5. The de Broglie wavelength is:

A. \lambda=hp

B. \lambda=p/h

C. \lambda=h/p

D. \lambda=hE

Urdu: De Broglie wavelength ka durust formula kya hai?

Q6. An electron and a proton have equal momentum. Their de Broglie wavelengths are:

A. Equal

B. Greater for the proton

C. Greater for the electron

D. Dependent only on charge

Urdu: Agar electron aur proton ka momentum barabar ho, to un ki de Broglie wavelengths kaisi hongi?

Q7. The stopping potential in a photoelectric experiment is 3 V. The maximum kinetic energy is:

A. 1.5 eV

B. 3 eV

C. 6 eV

D. 9 eV

Urdu: Agar photoelectric experiment mein stopping potential 3 V ho, to electrons ki maximum kinetic energy kya hogi?

Q8. The Davisson–Germer experiment confirmed:

A. Quantisation of electric charge

B. The nuclear model of the atom

C. The wave nature of electrons

D. Constancy of the speed of light

Urdu: Davisson–Germer experiment ne kis cheez ki tasdeeq ki?

Numerical and Conceptual Questions

Q9. Numerical

Light of wavelength 400 nm falls on a metal with a work function of 2.0 eV. Calculate the maximum kinetic energy of emitted electrons.

Use:

[ E_\gamma(\text{eV})\approx\frac{1240}{\lambda(\text{nm})} ]

Urdu: 400 nm wavelength ki roshni 2.0 eV work function wale ma'adin par parti hai. Nikalne wale electrons ki maximum kinetic energy maloom karein.

Q10. Numerical

An electron has momentum:

[ p=3.315\times10^{-24},\text{kg m s}^{-1} ]

Calculate its de Broglie wavelength.

Given:

[ h=6.63\times10^{-34},\text{J s} ]

Urdu: Ek electron ka momentum diya gaya hai. De Broglie wavelength calculate karein.

Q11. Assertion–Reason

Assertion (A): Increasing the intensity of light above the threshold frequency generally increases photoelectric current, other relevant conditions remaining unchanged.

Reason (R): At fixed frequency, greater intensity generally means more incident photons per second, potentially releasing more electrons.

A. Both A and R are true, and R correctly explains A.

B. Both are true, but R does not explain A.

C. A is true, but R is false.

D. A is false, but R is true.

Urdu:

Bayan (A): Threshold frequency se zyada frequency par roshni ki intensity barhane se aam taur par photoelectric current barhta hai.

Wajah (R): Ek hi frequency par intensity barhne ka matlab aam taur par zyada photons ka har second satah par girna hai, jis se zyada electrons nikal sakte hain.

Q12. Conceptual Question

The threshold frequency of a metal is 5\times10^{14},\text{Hz}. If the incident frequency is increased from 8\times10^{14},\text{Hz}, what happens to maximum kinetic energy?

A. It decreases.

B. It remains constant.

C. It increases.

D. It becomes zero.

Urdu: Ek ma'adin ki threshold frequency 5\times10^{14},\text{Hz} hai. Agar incident light ki frequency 8\times10^{14},\text{Hz} se mazeed barhai jaye, to maximum kinetic energy par kya asar hoga?

Physics Answer Key / Jawabat

Question

Answer

1

A

2

B

3

B

4

D

5

C

6

A

7

B

8

C

9

1.10 eV

10

2.0\times10^{-10},\text{m}

11

A

12

C

Physics Explanations / Wazahat

Q1. Photon Energy

[ E=hf ]

Photon ki energy us ki frequency ke mutabiq hoti hai. Frequency jitni zyada hogi, photon ki energy utni zyada hogi.

Q2. Threshold Frequency

[ f_0=\frac{\phi}{h} ]

Work function ko joules mein badlein:

[ \phi=2\times1.6\times10^{-19} =3.2\times10^{-19},\text{J} ]

[ f_0=\frac{3.2\times10^{-19}} {6.63\times10^{-34}} ]

[ \boxed{f_0\approx4.8\times10^{14},\text{Hz}} ]

Urdu: Threshold frequency woh minimum frequency hai jis par photoelectric emission shuru ho sakta hai.

Q3. Maximum Kinetic Energy

Einstein ka photoelectric equation:

[ K_{\max}=hf-\phi ]

Maximum kinetic energy incident light ki frequency par munhasir hoti hai, jab ke work function ma'adin ki khasusiyat hai.

Q4. Frequency Below Threshold

Agar har photon ki energy work function se kam ho, to aam single-photon model ke mutabiq electron nikal nahin sakta. Sirf intensity barhane se har photon ki energy nahin barhti.

Q5. De Broglie Wavelength

[ \lambda=\frac{h}{p} ]

Yahan h Planck constant aur p momentum hai.

Q6. Equal Momentum

Dono particles ka momentum barabar hai, is liye:

[ \lambda=\frac{h}{p} ]

Un ki wavelengths bhi barabar hongi.

Q7. Stopping Potential

[ K_{\max}=eV_s ]

3 V stopping potential ke liye maximum kinetic energy 3 eV hogi.

Q8. Davisson–Germer Experiment

Is experiment ne electron diffraction ke zariye electrons ki wave nature ki tasdeeq ki.

Q9. Numerical Solution

[ E_\gamma=\frac{1240}{400}=3.10,\text{eV} ]

[ K_{\max}=E_\gamma-\phi ]

[ K_{\max}=3.10-2.00 ]

[ \boxed{K_{\max}=1.10,\text{eV}} ]

Urdu: Pehle photon ki energy maloom karein, phir us mein se work function minus karein.

Q10. Numerical Solution

[ \lambda=\frac{h}{p} ]

[ \lambda= \frac{6.63\times10^{-34}} {3.315\times10^{-24}} ]

[ \boxed{\lambda=2.0\times10^{-10},\text{m}} ]

Q11. Assertion–Reason

Dono bayan durust hain. Ek hi frequency par intensity barhane se aam taur par har second zyada photons aate hain, jis se photoelectric current barh sakta hai.

Q12. Frequency and Kinetic Energy

[ K_{\max}=h(f-f_0) ]

Threshold frequency must remain fixed. Incident frequency barhne par maximum kinetic energy barhegi.

Physics Quick Revision / Mukhtasar Muraja'at

Photon energy: E=hf=hc/\lambda

Einstein equation: K_{\max}=hf-\phi

Threshold frequency: f_0=\phi/h

Stopping potential: K_{\max}=eV_s

De Broglie wavelength: \lambda=h/p

Fixed frequency par intensity barhane se aam taur par photoelectric current barhta hai.

Frequency barhane se maximum kinetic energy barhti hai.

Exam Tip: Intensity aur frequency ke asraat ko ek jaisa na samjhein.

SECTION B: CHEMISTRY

Chapter: Chemical Kinetics

Kimiyai Raftar-e-Amal

Multiple-Choice Questions

Q13. For the reaction A\rightarrow\text{Products}, the rate of disappearance of A is:

A. \dfrac{d[A]}{dt}

B. -\dfrac{d[A]}{dt}

C. \dfrac{d[A]}{dT}

D. -\dfrac{dT}{d[A]}

Urdu: Reaction A\rightarrow\text{Products} mein A ke khatam hone ki raftar kis formula se zahir hoti hai?

Q14. The half-life of a first-order reaction is:

A. Directly proportional to initial concentration

B. Inversely proportional to initial concentration

C. Independent of initial concentration

D. Always equal to the rate constant

Urdu: First-order reaction ka half-life initial concentration se kis tarah mutasir hota hai?

Q15. The unit of the rate constant for a first-order reaction is:

A. \text{mol L}^{-1}\text{s}^{-1}

B. \text{s}^{-1}

C. \text{L mol}^{-1}\text{s}^{-1}

D. \text{mol}^{-1}\text{s}^{-1}

Q16. The integrated rate equation for a zero-order reaction is:

A. [A]_t=[A]_0-kt

B. \ln[A]_t=\ln[A]_0-kt

C. \dfrac{1}{[A]_t}=\dfrac{1}{[A]_0}+kt

D. [A]_t=[A]_0e^{kt}

Q17. The half-life of a first-order reaction is 20 minutes. How long does it take for 75% completion?

A. 10 minutes

B. 20 minutes

C. 30 minutes

D. 40 minutes

Urdu: Ek first-order reaction ka half-life 20 minute hai. Reaction ke 75% mukammal hone mein kitna waqt lagega?

Q18. The Arrhenius equation is:

A. k=Ae^{-E_a/RT}

B. k=Ae^{E_a/RT}

C. k=E_a/RT

D. k=ART/E_a

Q19. A catalyst generally increases reaction rate by:

A. Increasing overall enthalpy change

B. Increasing the equilibrium constant

C. Providing an alternative pathway with lower activation energy

D. Increasing the free-energy change

Q20. For the rate law

[ r=k[A]^2[B] ]

the overall order of reaction is:

A. 1

B. 2

C. 3

D. 4

Numerical and Conceptual Questions

Q21. Numerical

A first-order reaction has:

[ k=0.0231,\text{min}^{-1} ]

Calculate its half-life.

[ t_{1/2}=\frac{0.693}{k} ]

Urdu: Ek first-order reaction ka rate constant diya gaya hai. Is ka half-life calculate karein.

Q22. Numerical

A zero-order reaction has an initial concentration of 0.80,\text{mol L}^{-1}. Its rate constant is 0.02,\text{mol L}^{-1}\text{min}^{-1}.

Calculate the concentration remaining after 15 minutes, assuming the reaction has not finished before that time.

Urdu: Ek zero-order reaction ki initial concentration 0.80,\text{mol L}^{-1} aur rate constant 0.02,\text{mol L}^{-1}\text{min}^{-1} hai. 15 minute baad baqi concentration maloom karein.

Q23. Assertion–Reason

Assertion (A): The half-life of a first-order reaction is independent of its initial concentration.

Reason (R):

[ t_{1/2}=\frac{0.693}{k} ]

A. Both A and R are true, and R correctly explains A.

B. Both are true, but R does not explain A.

C. A is true, but R is false.

D. A is false, but R is true.

Urdu:

Bayan (A): First-order reaction ka half-life initial concentration se azad hota hai.

Wajah (R): Is reaction ke liye half-life ka formula 0.693/k hai.

Q24. Conceptual Question

Increasing temperature significantly increases the rate constant. The best explanation is:

A. Activation energy necessarily becomes zero.

B. A greater fraction of molecules has energy equal to or greater than the activation energy.

C. The equilibrium constant must always increase.

D. The catalyst is consumed more rapidly.

Urdu: Temperature barhane se reaction ka rate constant barh jata hai. Is ki behtareen wajah kya hai?

Q25. Numerical

A first-order reaction has:

[ k=0.0693,\text{min}^{-1} ]

What fraction of the original reactant remains after 20 minutes?

[ [A]_t=[A]_0e^{-kt} ]

A. 1/2

B. 1/4

C. 1/8

D. 3/4

Urdu: 20 minute baad initial reactant ka kitna hissa baqi rahega?

Q26. Conceptual Question

The experimentally determined rate law is:

[ r=k[A][B]^2 ]

What is the overall order of the reaction?

A. 1

B. 2

C. 3

D. Cannot be determined from the rate law

Chemistry Answer Key / Jawabat

Question

Answer

13

B

14

C

15

B

16

A

17

D

18

A

19

C

20

C

21

30 minutes

22

0.50,\text{mol L}^{-1}

23

A

24

B

25

B

26

C

Chemistry Explanations / Wazahat

Q13. Rate of Disappearance

Reactant concentration waqt ke saath kam hoti hai, is liye rate of disappearance ko negative sign se likha jata hai:

[ -\frac{d[A]}{dt} ]

Q14. First-Order Half-Life

[ t_{1/2}=\frac{0.693}{k} ]

Is formula mein initial concentration maujood nahin. Is liye first-order reaction ka half-life initial concentration se azad hota hai.

Q15. Unit of Rate Constant

First-order reaction ke rate constant ki unit inverse time hoti hai:

[ \boxed{\text{s}^{-1}} ]

Agar waqt minute mein ho to unit \text{min}^{-1} hogi.

Q16. Zero-Order Reaction

Integrated rate equation:

[ [A]_t=[A]_0-kt ]

Q17. Time for 75% Completion

Agar 75% reaction mukammal ho gayi, to 25% reactant baqi hai.

[ [A]_0\rightarrow\frac{[A]_0}{2} \rightarrow\frac{[A]_0}{4} ]

Do half-lives darkar honge:

[ t=2\times20 ]

[ \boxed{t=40\text{ minutes}} ]

Q18. Arrhenius Equation

[ k=Ae^{-E_a/(RT)} ]

Yahan A pre-exponential factor, E_a activation energy, R gas constant aur T absolute temperature hai.

Q19. Catalyst

Catalyst kam activation energy wala alternative reaction pathway deta hai. Ek hi temperature par catalyst equilibrium constant ko tabdeel nahin karta.

Q20. Overall Order

[ r=k[A]^2[B] ]

Overall order:

[ 2+1=\boxed{3} ]

Q21. Half-Life Calculation

[ t_{1/2}=\frac{0.693}{0.0231} ]

[ \boxed{t_{1/2}=30\text{ minutes}} ]

Q22. Zero-Order Numerical

[ [A]_t=[A]_0-kt ]

Values rakhne par:

[ [A]_t=0.80-(0.02\times15) ]

[ [A]_t=0.80-0.30 ]

[ \boxed{[A]_t=0.50,\text{mol L}^{-1}} ]

Q23. Assertion–Reason

Dono statements durust hain. First-order reaction ka half-life rate constant par munhasir hota hai, initial concentration par nahin.

Q24. Temperature Effect

Temperature barhne par zyada molecules ko activation-energy barrier paar karne ke liye kafi energy milti hai. Is liye aam taur par rate constant barhta hai.

Q25. Fraction Remaining

[ \frac{[A]_t}{[A]_0}=e^{-kt} ]

[ =e^{-(0.0693)(20)} ]

[ =e^{-1.386} ]

Kyun ke 1.386\approx\ln4,

[ \boxed{\frac{[A]_t}{[A]_0}=\frac14} ]

Yani initial reactant ka one-quarter hissa baqi rahega.

Q26. Overall Order

Rate law mein concentrations ki powers jama karein:

[ 1+2=\boxed{3} ]

Chemistry Quick Revision / Mukhtasar Muraja'at

Reaction Order

Integrated Rate Equation

Half-Life

Zero order

[A]_t=[A]_0-kt

\dfrac{[A]_0}{2k}

First order

\ln([A]_0/[A]_t)=kt

\dfrac{0.693}{k}

Second order, one reactant

\dfrac{1}{[A]_t}-\dfrac{1}{[A]_0}=kt

\dfrac{1}{k[A]_0}

Remember / Yaad Rakhein:

Reaction order experiment se determine hota hai.

Molecularity elementary reaction step par apply hoti hai.

Catalyst reaction pathway ko badalta hai, lekin fixed temperature par equilibrium constant ko nahin.

First-order reaction mein do half-lives ke baad one-quarter reactant baqi rehta hai.

Arrhenius equation mein temperature Kelvin mein hona chahiye.

SECTION C: BIOLOGY

Chapter: Biodiversity and Conservation

Hayati Tanawwu aur Tahaffuz

Multiple-Choice Questions

Q27. Biodiversity includes diversity at which levels?

A. Genetic diversity only

B. Species diversity only

C. Ecosystem diversity only

D. Genetic, species and ecosystem diversity

Urdu: Hayati tanawwu mein kin satahon ki diversity shamil hoti hai?

Q28. A region with many endemic species and substantial habitat loss is commonly called a:

A. Desert biome

B. Biodiversity hotspot

C. Tundra region

D. Buffer zone only

Urdu: Aisa ilaqa jahan endemic species zyada hon aur habitat ka kaafi nuqsan hua ho, kya kehlata hai?

Q29. Which is an example of in situ conservation?

A. Keeping endangered plants in a botanical garden

B. Preserving seeds in a seed bank

C. Protecting wildlife in its natural habitat in a national park

D. Breeding endangered animals in a zoo

Urdu: In situ conservation ki misaal kaun si hai?

Q30. Which is an example of ex situ conservation?

A. Protecting a forest ecosystem

B. Establishing a wildlife sanctuary

C. Maintaining threatened species in a zoological park

D. Preventing habitat destruction in a national park

Urdu: Ex situ conservation ki misaal kaun si hai?

Q31. The species–area relationship is commonly expressed as:

A. S=CA^Z

B. S=C/A

C. S=A+Z

D. S=Z/A^2

Urdu: Species–area relationship ko aam taur par kis equation se zahir kiya jata hai?

Q32. In the log–log plot of the species–area relationship, the slope represents:

A. C

B. Z

C. S

D. A

Urdu: Species–area relationship ke log–log graph ki slope kya zahir karti hai?

Q33. The rivet-popper hypothesis suggests that:

A. Species loss never affects ecosystem functioning.

B. Every species has exactly the same ecological role.

C. Species loss can weaken ecosystem functioning and stability.

D. Only large animals matter to ecosystems.

Urdu: Rivet-popper hypothesis kis baat ki taraf ishara karti hai?

Q34. Major causes of biodiversity loss include:

A. Habitat loss and fragmentation

B. Overexploitation

C. Invasion by alien species

D. All of the above

Urdu: Hayati tanawwu mein kami ke bunyadi asbab kaun se hain?

Assertion–Reason and Application Questions

Q35. Assertion–Reason

Assertion (A): Endemic species can be especially vulnerable when their restricted habitats are destroyed.

Reason (R): Endemic species naturally occur within a limited geographical area.

A. Both A and R are true, and R correctly explains A.

B. Both are true, but R does not explain A.

C. A is true, but R is false.

D. A is false, but R is true.

Urdu:

Bayan (A): Endemic species apne mehdood habitat ke khatam hone par khaas taur par khatre mein aa sakti hain.

Wajah (R): Endemic species fitri taur par mehdood ilaqe mein pai jati hain.

Q36. Assertion–Reason

Assertion (A): Ex situ conservation can be useful when a species faces serious danger in its natural habitat.

Reason (R): Ex situ conservation may maintain threatened organisms outside their natural habitats under managed conditions.

A. Both A and R are true, and R correctly explains A.

B. Both are true, but R does not explain A.

C. A is true, but R is false.

D. A is false, but R is true.

Urdu:

Bayan (A): Jab kisi species ko natural habitat mein shadeed khatra ho, to ex situ conservation faida mand ho sakti hai.

Wajah (R): Is tareeqe mein khatre se dochar organisms ko natural habitat se bahar controlled conditions mein rakha ja sakta hai.

Q37. Application-Based Question

A forest is divided into several small, isolated patches by roads and construction. What is a major conservation concern?

A. All species immediately become more abundant.

B. Fragmentation can restrict movement and gene flow between populations.

C. Fragmentation guarantees increased genetic diversity.

D. The ecosystem automatically returns to its original state.

Urdu: Ek jungle roads aur construction ki wajah se chhote, alag alag hisson mein taqseem ho jata hai. Conservation ke liye sab se bara khatra kya hai?

Q38. Conceptual Question

Which statement about biodiversity and ecosystem functioning is most scientifically appropriate?

A. Every ecosystem requires exactly the same number of species.

B. Species richness alone completely determines every ecosystem process.

C. Biodiversity can support ecosystem functioning, resilience and ecosystem services, although effects vary by ecosystem and function.

D. Species diversity has no relationship with ecosystem functioning.

Urdu: Hayati tanawwu aur ecosystem functioning ke bare mein sab se durust scientific bayan kaun sa hai?

Biology Answer Key / Jawabat

Question

Answer

27

D

28

B

29

C

30

C

31

A

32

B

33

C

34

D

35

A

36

A

37

B

38

C

Biology Explanations / Wazahat

Q27. Levels of Biodiversity

Biodiversity ki teen bunyadi satahein hain:

Genetic diversity: Ek hi species ke organisms ke genes mein farq.

Species diversity: Kisi ilaqe mein mukhtalif species ki variety.

Ecosystem diversity: Mukhtalif habitats aur ecosystems ki variety.

Urdu: Hayati tanawwu sirf species ki tadaad ka naam nahin. Is mein genetic aur ecosystem level par diversity bhi shamil hai.

Q28. Biodiversity Hotspot

Aisa ilaqa jahan endemic species ki kasrat ho aur habitat ka numaya nuqsan hua ho, biodiversity hotspot kehlata hai.

Q29. In Situ Conservation

Species ko un ke natural habitat mein mehfooz rakhna in situ conservation hai.

Examples:

National parks

Wildlife sanctuaries

Biosphere reserves

Q30. Ex Situ Conservation

Species ko un ke natural habitat se bahar mehfooz rakhna ex situ conservation hai.

Examples:

Zoos

Botanical gardens

Seed banks

Gene banks

Q31. Species–Area Relationship

[ S=CA^Z ]

Yahan:

S = species ki tadaad

A = area

C = constant

Z = exponent

Q32. Log–Log Plot

Logarithmic form:

[ \log S=\log C+Z\log A ]

Is equation mein slope Z hoti hai aur intercept \log C hota hai.

Q33. Rivet-Popper Hypothesis

Is hypothesis mein ecosystem ka muqabla hawai jahaz se aur species ka muqabla rivets se kiya jata hai. Kuch rivets nikalne se jahaz foran nahin toot ta, lekin musalsal rivets nikalne se us ki structure kamzor ho sakti hai.

Isi tarah, species ka musalsal zaya hona ecosystem ki functioning aur stability ko nuqsan pohncha sakta hai.

Q34. Causes of Biodiversity Loss

Bunyadi asbab:

Habitat loss and fragmentation

Overexploitation

Invasive alien species

Co-extinctions

Q35. Endemic Species

Dono statements durust hain. Endemic species mehdood ilaqe mein pai jati hain. Is liye us ilaqe ka habitat khatam hone par species ki bari population ya poori species khatre mein aa sakti hai.

Q36. Ex Situ Conservation

Dono statements durust hain. Ex situ conservation threatened species ko protection, breeding aur research ke liye controlled conditions de sakti hai. Munasib surat mein future reintroduction mein bhi madad mil sakti hai.

Lekin yeh natural habitats ko protect karne ka badal nahin hai.

Q37. Habitat Fragmentation

Habitat fragmentation se:

Organisms ki movement mehdood ho sakti hai.

Populations ke darmiyan gene flow kam ho sakta hai.

Edge effects barh sakte hain.

Chhoti populations mein local extinction ka risk barh sakta hai.

Q38. Biodiversity and Ecosystem Functioning

Biodiversity productivity, nutrient cycling, resilience aur ecosystem services ko support kar sakti hai. Is ka asar ecosystem, species aur ecological process ke mutabiq mukhtalif ho sakta hai.

Biology Quick Revision / Mukhtasar Muraja'at

Biodiversity ke teen levels: genetic, species aur ecosystem diversity.

In situ conservation: natural habitat mein protection.

Ex situ conservation: natural habitat se bahar protection.

Major threats: habitat loss, fragmentation, overexploitation, invasive alien species aur co-extinction.

Species–area relationship:

[ S=CA^Z ]

Logarithmic form:

[ \log S=\log C+Z\log A ]

Endemic species ka geographical distribution mehdood hota hai.

Biodiversity ka tahaffuz environment aur insani muashray dono ke liye aham hai.

SECTION D: FULL PRACTICE TEST SUMMARY

Mukammal Mashqi Test ka Khulasa

Subject

Questions

Skills Tested

Physics

12

Formula application, calculations, conceptual reasoning

Chemistry

14

Rate laws, reaction order, half-life and numericals

Biology

12

NCERT concepts, conservation and applications

Total

38

Conceptual and numerical practice

Self-Assessment / Apni Tayyari Ka Jaiza

Yeh scale sirf is practice set ke liye hai. Yeh official NEET score prediction nahin hai.

34–38 correct: Bohat achhi performance. Ghaltiyon ko analyse karein aur concepts revise karein.

28–33 correct: Achhi progress. Multi-step reasoning aur numericals par mazeed practice karein.

20–27 correct: Chapter summaries dobara parhein aur numericals phir hal karein.

20 se kam correct: Pehle basic concepts mazboot karein, phir test dobara dein.

Apni poori tayari ka faisla sirf ek test se na karein. Mukhtalif timed tests mein consistency, accuracy aur ghaltiyon ki correction zyada aham hai.

SECTION E: SEVEN-DAY REVISION PLAN

Saat Din ka Revision Plan

Day 1 — Physics Fundamentals

Photon energy, work function, threshold frequency aur Einstein photoelectric equation revise karein. Kam az kam 15 numerical questions hal karein.

Urdu: Bunyadi formulas samjhein aur numerical practice karein.

Day 2 — Matter Waves

De Broglie wavelength, momentum aur electron diffraction se mutalliq sawalat hal karein.

Day 3 — Chemical Kinetics Basics

Average aur instantaneous rate, rate law, reaction order aur rate constant ki units revise karein.

Day 4 — Chemical Kinetics Numericals

Zero-order aur first-order equations, half-life aur Arrhenius equation ki practice karein.

Day 5 — Biodiversity

Biodiversity ke teen levels, hotspots, endemic species aur biodiversity loss ke major causes revise karein.

Day 6 — Conservation Strategies

In situ aur ex situ conservation ka farq samjhein. Species–area relationship aur habitat fragmentation par questions solve karein.

Day 7 — Mock Test and Error Analysis

38 sawalat ko waqt muqarrar karke hal karein. Har ghalti ko in categories mein rakhein:

Conceptual mistake

Wrong formula

Calculation error

Question ko ghalat parhna

Baghair kafi daleel ke guess karna

Har ghalat sawal dobara hal karein aur ek jumle mein likhein ke sahi jawab kyun durust hai.

SECTION F: FINAL EXAM STRATEGY

Imtihan ki Aakhri Hikmat-e-Amali

1. Read carefully / Sawal tawajjoh se parhein.

Maximum, minimum, incorrect, threshold aur independent jaise alfaaz par khaas tawajjoh dein.

2. Write the formula first / Pehle formula likhein.

Khaas taur par photoelectric effect aur chemical kinetics ke numericals mein.

3. Check units / Units check karein.

Zaroorat par eV ko joules mein tabdeel karein. Rate constant aur time ki units ek doosre ke mutabiq rakhein.

4. Distinguish similar concepts / Milte-julte concepts ka farq samjhein.

Photoelectric current aur maximum kinetic energy ek cheez nahin. Reaction order aur molecularity bhi mukhtalif hain. In situ aur ex situ conservation mein bhi farq hai.

5. Analyse mistakes / Ghaltiyon ka tajziya karein.

Ek hi qisam ki ghalti ko dobara na dohrana, sirf zyada sawalat hal karne se zyada mufeed ho sakta hai.

6. Use NCERT for Biology / Biology ke liye NCERT par tawajjoh dein.

Definitions aur ecological relationships ko sahi samjhein. Jawabat ko prescribed syllabus aur textbook se milayein.

DISCLAIMER

Aham Taleemi Wazahat

This practice set has been independently prepared for NEET UG 2027 preparation. It is not an official NTA publication, does not reproduce an official examination paper and does not guarantee that any question will appear in NEET 2027.

Yeh mashqi sawalat, answer key aur explanations revision aur self-assessment ke liye hain. Students ko latest official examination notification, prescribed syllabus, NCERT textbooks aur reliable educational resources follow karne chahiye.

Examination pattern, eligibility conditions aur syllabus ki tabdeeliyon ko official sources se verify karein.

Kisi khaas score, rank, admission ya examination result ki guarantee nahin di jati. Is material ko regular study, mock tests aur error analysis ke saath istemal karein.

META DESCRIPTION

Prepare for NEET UG 2027 with Part 89 of this English–Urdu practice series. Study Physics Dual Nature of Matter and Radiation, Chemistry Chemical Kinetics, and Biology Biodiversity and Conservation with MCQs, numerical questions, answer keys, detailed explanations and a seven-day revision plan.

Urdu: NEET UG 2027 ki tayari ke liye Part 89 ka English–Urdu practice set. Physics, Chemistry aur Biology ke MCQs, numericals, answer keys, detailed explanations aur seven-day revision plan ke saath.

KEYWORDS

NEET 2027 Possible Questions Part 89, NEET English Urdu, NEET UG 2027 preparation, Dual Nature of Matter and Radiation, Photoelectric Effect, De Broglie Wavelength, Chemical Kinetics MCQs, First Order Reaction, Half-Life Numericals, Biodiversity and Conservation, NEET Biology Questions, NEET Mock Test, NEET Answer Key, NEET Revision Plan.

HASHTAGS

#NEET2027 #NEETUG #NEETPreparation #EnglishUrdu #NEETPhysics #DualNatureOfMatter #PhotoelectricEffect #NEETChemistry #ChemicalKinetics #NEETBiology #Biodiversity #Conservation #MCQPractice #NEETMockTest #NCERT #MedicalEntranceExam #StudySmart #ExamPreparation

FINAL MOTIVATION / AAKHRI PAIGHAM

Dear friend, your goal is not simply to finish a chapter. Your goal is to understand it well enough to solve an unfamiliar question under examination pressure.

Learn the concept. Apply the formula. Check the units. Analyse the mistake. Revise the concept. Repeat the process.

Urdu: Dost, sirf chapter khatam karna maqsad nahin hai. Asal maqsad concepts ko itna achhi tarah samajhna hai ke imtihan ke dabao mein bhi naye sawalat hal kar sako.

Concept samjho. Formula lagao. Units check karo. Ghalti ka tajziya karo. Dobara practice karo.

Har roz ki mehnat tumhari tayari ko mazboot bana sakti hai. Har ghalti ko seekhne ka mauqa samjho aur apni manzil ki taraf lagataar barhte raho.

دوست، keep going! ❤️ Consistent practice, a strong understanding of NCERT, and learning from mistakes can make your NEET 2027 preparation stronger day by day.